k-Clique (Clique Problems)

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Revision as of 10:22, 15 February 2023 by Admin (talk | contribs) (Created page with "{{DISPLAYTITLE:k-Clique (Clique Problems)}} == Description == For a constant $k \geq 3$, the $k$-Clique problem is as follows: given a graph $G = (V, E)$ on $n$ vertices, does $G$ contain $k$ distinct vertices $a_1, \ldots, a_k$ so that for every $(i, j)$, $i \neq j$, $(a_i, a_j ) \in E$? Such a $k$ node graph is called a $k$-clique. == Related Problems == Subproblem: Exact k-Clique, Min-Weight k-Clique, Max-Weight k-Clique Related: Enumerating Maxi...")
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Description

For a constant $k \geq 3$, the $k$-Clique problem is as follows: given a graph $G = (V, E)$ on $n$ vertices, does $G$ contain $k$ distinct vertices $a_1, \ldots, a_k$ so that for every $(i, j)$, $i \neq j$, $(a_i, a_j ) \in E$? Such a $k$ node graph is called a $k$-clique.

Related Problems

Subproblem: Exact k-Clique, Min-Weight k-Clique, Max-Weight k-Clique

Related: Enumerating Maximal Cliques, arbitrary graph, Min-Weight k-Clique, Max-Weight k-Clique

Parameters

n: number of vertices
k: size of clique

Table of Algorithms

Currently no algorithms in our database for the given problem.

Reductions TO Problem

Problem Implication Year Citation Reduction
CFG Recognition assume: k-Clique Hypothesis
then: there is no $O(N^{\omega-\epsilon}) time algorithm for target for any $\epsilon > {0}$
2017 https://ieeexplore-ieee-org.ezproxy.canberra.edu.au/abstract/document/8104058 link
RNA Folding assume: k-Clique Hypothesis
then: there is no $O(N^{\omega-\epsilon}) time algorithm for target for any $\epsilon > {0}$
2017 https://ieeexplore-ieee-org.ezproxy.canberra.edu.au/abstract/document/8104058 link
CFG Recognition assume: k-Clique Hypothesis
then: there is no $O(N^{\{3}-\epsilon}) time combinatorial algorithm for target for any $\epsilon > {0}$
2017 https://ieeexplore-ieee-org.ezproxy.canberra.edu.au/abstract/document/8104058 link
RNA Folding assume: k-Clique Hypothesis
then: there is no $O(N^{\{3}-\epsilon}) time combinatorial algorithm for target for any $\epsilon > {0}$
2017 https://ieeexplore-ieee-org.ezproxy.canberra.edu.au/abstract/document/8104058 link

References/Citation

https://dml.cz/bitstream/handle/10338.dmlcz/106381/CommentatMathUnivCarol_026-1985-2_22.pdf