Maximum Inner Product Search (Maximum Inner Product Search)

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Revision as of 10:30, 15 February 2023 by Admin (talk | contribs) (Created page with "{{DISPLAYTITLE:Maximum Inner Product Search (Maximum Inner Product Search)}} == Description == Given a new query $q$, MIPS targets at retrieving the datum having the largest inner product with $q$ from the database $A$. Formally, the MIPS problem is formulated as below: $p = \arg \max \limits_{a \in A} a \top q$ == Parameters == No parameters found. == Table of Algorithms == Currently no algorithms in our database for the given problem. == Reductions TO Problem...")
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Description

Given a new query $q$, MIPS targets at retrieving the datum having the largest inner product with $q$ from the database $A$. Formally, the MIPS problem is formulated as below:

$p = \arg \max \limits_{a \in A} a \top q$

Parameters

No parameters found.

Table of Algorithms

Currently no algorithms in our database for the given problem.

Reductions TO Problem

Problem Implication Year Citation Reduction
Boolean d-Attribute Stable Matching assume: OVH
then: for an $\epsilon > {0}$ there is a $c$ such that finding a stable matching in the boolean $d$-attribute model with $d = c\log n$ dimensions requires time $\Omega(n^{2-\epsilon})$.
2016 https://arxiv.org/pdf/1510.06452.pdf link
Stable Matching Verification assume: OVH
then: for an $\epsilon > {0}$ there is a $c$ such that verifying a stable matching in the boolean $d$-attribute model with $d = c\log n$ dimensions requires time $\Omega(n^{2-\epsilon}).
2016 https://arxiv.org/pdf/1510.06452.pdf link
Stable Pair Checking assume: OVH
then: for any $\epsilon > {0}$, there is a $c$ such that determining whether a given pair is part of any or all stable matchings in the boolean $d$-attribute model with $d = c\log n$ dimensions requires time $\Omega(n^{2-\epsilon})$
2016 https://arxiv.org/pdf/1510.06452.pdf link
Stable Pair Checking assume: NSETH
then: for any $\epsilon > {0}$ there is a $c$ such that determining whether a gaiven pair is part of any or all stable matching in the boolean $d$-attribute model with $d = c\log n$ dimensions requires co-nondeterministic time $\Omega(n^{2-\epsilon})$
2016 https://arxiv.org/pdf/1510.06452.pdf link
Stable Pair Checking assume: NSETH
then: for any $\epsilon > {0}$ there is a $c$ such that determining whether a gaiven pair is part of any or all stable matching in the boolean $d$-attribute model with $d = c\log n$ dimensions requires nondeterministic time $\Omega(n^{2-\epsilon})$
2016 https://arxiv.org/pdf/1510.06452.pdf link